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33eb3028f5
tests/accumulator/*.m:
tests/analysis_*/*.m:
tests/benchmarks*/*.m:
tests/debugger*/*.{m,exp,inp}:
tests/declarative_debugger*/*.{m,exp,inp}:
tests/dppd*/*.m:
tests/exceptions*/*.m:
tests/general*/*.m:
tests/grade_subdirs*/*.m:
tests/hard_coded*/*.m:
Make these tests use four-space indentation, and ensure that
each module is imported on its own line. (I intend to use the latter
to figure out which subdirectories' tests can be executed in parallel.)
These changes usually move code to different lines. For the debugger tests,
specify the new line numbers in .inp files and expect them in .exp files.
144 lines
4.8 KiB
Plaintext
144 lines
4.8 KiB
Plaintext
E1: C1 CALL pred info.main/2-0 (det) info.m:18
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mdb> mdb> Contexts will not be printed.
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mdb> echo on
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Command echo enabled.
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mdb> break info.last
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0: + stop interface pred info.last/2-0 (semidet)
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mdb> c
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E2: C2 CALL pred info.last/2-0 (semidet)
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mdb> delete *
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0: E stop interface pred info.last/2-0 (semidet)
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mdb> f
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E3: C2 EXIT pred info.last/2-0 (semidet)
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mdb> dd -d 3 -n 7 -s divide_and_query
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last([1, 2, 3, 4, 5, 6, 7, 8, ...], t/1)
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Valid? info
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Context of current question : info.m:48 (info.m:20)
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Search mode : divide and query
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Estimated questions remaining : 5
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Number of suspect events : 30
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The current question was chosen because this is the node where the `dd'
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command was issued.
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dd> n
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last([6, 7, 8, 9, 10], t(10))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : divide and query
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Estimated questions remaining : 5
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Number of suspect events : 30
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The current question was chosen because this node divides the suspect
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area into two regions of 15 and 15 events each.
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dd> n
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last([9, 10], t(10))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : divide and query
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Estimated questions remaining : 4
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Number of suspect events : 15
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The current question was chosen because this node divides the suspect
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area into two regions of 9 and 6 events each.
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dd> q
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Diagnosis aborted.
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E3: C2 EXIT pred info.last/2-0 (semidet)
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mdb>
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E4: C3 CALL pred info.last/2-0 (semidet)
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mdb> f
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E5: C3 EXIT pred info.last/2-0 (semidet)
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mdb> dd -d 3 -n 7
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last([101, 112, 103, 104, 105, 106, 107, 108], t/1)
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Valid? n
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last([112, 103, 104, 105, 106, 107, 108], t(108))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : top down
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The current question was chosen because this is the next node in the
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top-down search.
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dd> b 2
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browser> mark
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last([108], t(108))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : top down
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The current question was chosen because the marked subterm was bound by
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the unification inside the predicate info.last/2 (info.m:48). The path
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to the subterm in the atom is 2.
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dd> mode binary
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last([105, 106, 107, 108], t(108))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : binary search on path
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The current question was chosen because this node divides a path of
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length 7 into two paths of length 3 and 4.
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dd> n
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last([107, 108], t(108))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : binary search on path
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The current question was chosen because this node divides a path of
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length 3 into two paths of length 1 and 2.
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dd> b 1
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browser> cd 1
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browser> mark
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last([106, 107, 108], t(108))
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Valid? info
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Context of current question : info.m:48 (info.m:50)
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Search mode : top down
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The current question was chosen because tracking of the marked subterm
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was stopped here, because the binding node lies in a portion of the tree
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which has been eliminated.
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dd> q
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Diagnosis aborted.
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E5: C3 EXIT pred info.last/2-0 (semidet)
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mdb> break q
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0: + stop interface pred info.q/4-0 (det)
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mdb> c
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E6: C4 CALL pred info.q/4-0 (det)
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mdb> delete *
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0: E stop interface pred info.q/4-0 (det)
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mdb> f
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E7: C4 EXIT pred info.q/4-0 (det)
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mdb> dd -d 3 -n 7
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q(0, "lala", t(t(t("lala"))), 2)
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Valid? b 3
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browser> cd 1/1
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browser> mark
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f(0, "lala") = t(t(t("lala")))
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Valid? info
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Context of current question : info.m:57 (info.m:39)
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Search mode : top down
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The current question was chosen because the marked subterm was bound by
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the unification inside the function info.f/3 (info.m:58). The path to
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the subterm in the atom is 3/1/1.
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dd> q
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Diagnosis aborted.
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E7: C4 EXIT pred info.q/4-0 (det)
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mdb>
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E8: C5 CALL pred info.q/4-0 (det)
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mdb> f
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E9: C5 EXIT pred info.q/4-0 (det)
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mdb> dd -d 3 -n 7
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q(1, "lala", t(t(t("lala"))), 2)
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Valid? b 4
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browser> mark
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fproc(1) = 2
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Valid? info
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Context of current question : info.m:63 (info.m:42)
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Search mode : top down
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The current question was chosen because the marked subterm was bound by
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the foreign procedure call inside the function info.fproc/2 (info.m:63).
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The path to the subterm in the atom is 2.
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dd> n
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Found incorrect contour:
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fproc(1) = 2
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Is this a bug? n
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fproc(1) = 2
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Valid? [no] info
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Context of current question : info.m:63 (info.m:42)
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Search mode : top down
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The current question was chosen because this question is being
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revisited, because of an unsuccessful previous bug search.
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dd> q
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Diagnosis aborted.
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E9: C5 EXIT pred info.q/4-0 (det)
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mdb> quit -y
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